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added some text to see how it looks

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Joshua Moerman 2013-02-28 21:52:08 +01:00
parent 1d0513f451
commit 68985a4a75
1 changed files with 18 additions and 6 deletions
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presentation/presentation.tex
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@ -1,4 +1,4 @@
\documentclass{beamer} \documentclass[14pt]{beamer}
\usepackage[dutch]{babel} \usepackage[dutch]{babel}
@ -9,11 +9,14 @@
\usepackage{listings} \usepackage{listings}
\newcommand{\id}{\text{id}} \newcommand{\id}{\text{id}}
\newcommand{\N}{\mathbb{N}}
\newcommand{\Z}{\mathbb{Z}}
\newcommand{\cat}[1]{\mathbf{#1}} \newcommand{\cat}[1]{\mathbf{#1}}
\newcommand{\eps}{\varepsilon} \newcommand{\eps}{\varepsilon}
\newcommand{\I}{\,\mid\,} \newcommand{\I}{\,\mid\,}
\newcommand{\then}{\Rightarrow} \newcommand{\then}{\Rightarrow}
\newcommand{\inject}{\hookrightarrow} \newcommand{\inject}{\hookrightarrow}
\newcommand{\del}{\partial}
\title{Dold-Kan correspondentie} \title{Dold-Kan correspondentie}
\author{Joshua Moerman} \author{Joshua Moerman}
@ -26,23 +29,32 @@
\titlepage \titlepage
\end{frame} \end{frame}
\begin{frame}
\frametitle{Dold-Kan Correspondentie}
\huge $$ \cat{Ch(Ab)} \simeq \cat{sAb} $$
\end{frame}
\section{Ketencomplex} \section{Ketencomplex}
\begin{frame} \begin{frame}
\frametitle{Ketencomplex} \frametitle{Ketencomplex}
\begin{definition} \begin{definition}
$C_n \in \cat{Ab}$ Een \emph{ketencomplex} $C$ bestaat uit abelse groepen $C_n$ en homomorfismes $\del_n : C_{n+1} \to C_n$, zodat $\del_n \circ \del_{n+1} = 0$ voor alle $n \in \N$.
\end{definition} \end{definition}
\pause \pause
Enzoverder \bigskip
Met andere woorden:
$$ \cdots \to C_4 \to C_3 \to C_2 \to C_1 \to C_0 $$
\end{frame} \end{frame}
\begin{frame}
Uit $\del_n \circ \del_{n+1} = 0$ volgt $im(\del_{n+1}) \trianglelefteq ker(\del_n)$
\pause
Definieer: $H_n(C) = ker(\del_n) / im(\del_{n+1})$
\end{frame}
\begin{frame} \begin{frame}
\begin{center} \begin{center}
\Huge Questions? \Huge Vragen?
\end{center} \end{center}
\end{frame} \end{frame}