@ -149,4 +149,32 @@ and the second map is obtained by the map $A \to A(K(A))$ and using the bijectio
To conclude that $B \to A(K(B))$ is a weak equivalence, we wish to prove that the front face of the cube is a homotopy pushout, as the back face clearly is one. This is a consequence of the Eilenberg-Moore spectral sequence \cite{mccleary}.
}
Now we wish to use the previous lemma as an induction step for minimal models.
Now we wish to use the previous lemma as an induction step for minimal models. Let $(\Lambda V, d)$ be some minimal algebra. Write $V(n+1)= V(n)\oplus V'$ and let $v \in V'$ of degree $\deg{v}= k$, then the minimal algebra $(\Lambda(V(n)\oplus\Q\cdot v), d)$ is the pushout in the following diagram, where $f$ sends the generator $c$ to $dv$.
In particular if the vector space $V'$ is finitely generated, we can repeat this procedure for all basis elements (it does not matter in what order we do so, as $dv \in\Lambda V(n)$). So in this case, if $(\Lambda V(n), d)\to A(K(\Lambda V(n), d))$ is a weak equivalence, so is $(\Lambda V(n+1), d)\to A(K(\Lambda V(n+1), d))$
\Corollary{}{
Let $(\Lambda V, d)$ be a $1$-connected minimal algebra with $V^i$ finite dimensional for all $i$. Then $(\Lambda V, d)\to A(K(\Lambda V, d))$ is a weak equivalence.
}
\Proof{
Note that if we want to prove the isomorphism $H^i(\Lambda V, d)\to H^i(A(K(\Lambda V, d)))$ it is enough to prove that $H^i(\Lambda V^{\leq i}, d)\to H^i(A(K(\Lambda V^{\leq i}, d)))$ is an isomorphism (as the elements of higher degree do not change the isomorphism). By the $1$-connectedness we can choose our filtration to respect the degree by \LemmaRef{1-reduced-minimal-model}.
Now $V(n)$ is finitely generated for all $n$ by assumption. By the inductive procedure above we see that $(\Lambda V(n), d)\to A(K(\Lambda V(n), d))$ is a weak equivalence for all $n$. Hence $(\Lambda V, d)\to A(K(\Lambda V, d))$ is a weak equivalence.
}
\todo{$X \to K(A(X))$}
We have proven the following theorem.
\Theorem{main-theorem}{
The functors $A$ and $K$ induce an equivalence of homotopy categories, when restricted to rational, $1$-connected objects of finite type. more formally, we have:
$$\Ho(\sSet_1^{\Q,f})\iso\Ho(\CDGA_{\Q,1,f}). $$
Furthermore, for any $1$-connected space $X$ of finite type, we have the following isomorphism of groups:
$$\pi_i(X)\tensor\Q\iso{V^i}^\ast, $$
where $(\Lambda V, d)$ is the minimal model of $A(X)$.
@ -26,14 +26,14 @@ In this section we will discuss the so called minimal models. These cdga's enjoy
We will often say \Def{minimal model} or \Def{minimal algebra} to mean minimal Sullivan model or minimal Sullivan algebra. In many cases we can take the degree of the elements in $V$ to induce the filtration, as seen in the following lemma of which the proof is left out, as we are not going to use it.
\begin{lemma}
\Lemma{1-reduced-minimal-model}{
Let $(A, d)$ be a cdga which is $1$-reduced, such that $A$ is free as cga and $d$ is decomposable. Then $(A, d)$ is a minimal algebra.
\end{lemma}
\begin{proof}
}
\Proof{
Let $V$ generate $A$. Take $V(n)=\bigoplus_{k=0}^n V^k$ (note that $V^0= V^1=0$). Since $d$ is decomposable we see that for $v \in V^n$: $d(v)= x \cdot y$ for some $x, y \in A$. Assuming $dv$ to be non-zero we can compute the degrees:
$$\deg{x}+\deg{y}=\deg{xy}=\deg{dv}=\deg{v}+1= n +1. $$
As $A$ is $1$-reduced we have $\deg{x}, \deg{y}\geq2$ and so by the above $\deg{x}, \deg{y}\leq n-1$. Conclude that $d(V(k))\subset\Lambda(V(n-1))$.
\end{proof}
}
The above definition is the same as in \cite{felix} without assuming connectivity. We find some different definitions of (minimal) Sullivan algebras in the literature. For example we find a definition using well orderings in \cite{hess}. The decomposability of $d$ also admits a different characterization (at least in the connected case). The equivalence of the definitions is expressed in the following two lemmas.