\subsection{$A$ and $K$ form a Quillen pair} We will prove that $A$ preserves cofibrations and trivial cofibrations. We only have to check this fact for the generating (trivial) cofibrations in $\sSet$. Note that the contravariance of $A$ means that a (trivial) cofibrations should be sent to a (trivial) fibration. \begin{lemma} $A(i) : A(\Delta[n]) \to A(\del \Delta[n])$ is surjective. \end{lemma} \begin{proof} Let $\phi \in A(\del \Delta[n])$ be an element of degree $k$, hence it is a map $\del \Delta[n] \to \Apl^k$. We want to extend this to the whole simplex. By the fact that $\Apl^k$ is Kan and contractible we can find a lift $\overline{\phi}$ in the following diagram showing the surjectivity. \cimage[scale=0.5]{Extend_Boundary_Form} \end{proof} \begin{lemma} $A(j) : A(\Delta[n]) \to A(\Lambda^n_k)$ is surjective and a quasi isomorphism. \end{lemma} \begin{proof} As above we get surjectivity from the Kan condition. To prove that $A(j)$ is a quasi isomorphism we pass to the singular cochain complex and use that $C^\ast(j) : C^\ast(\Delta[n]) \we C^\ast(\Lambda^n_k)$ is a quasi isomorphism. Consider the following diagram and conclude that $A(j)$ is surjective and a quasi isomorphism. \cimage[scale=0.5]{A_Preserves_WCof} \end{proof} Since $A$ is a left adjoint, it preserves all colimits and by functoriality it preserves retracts. From this we can conclude the following corollary. \begin{corollary} $A$ preserves all cofibrations and all trivial cofibrations and hence is a left Quillen functor. \end{corollary} \begin{corollary} $A$ and $K$ induce an adjunction on the homotopy categories: $$ \Ho{\sSet} \leftadj \opCat{\Ho{\CDGA}}. $$ \end{corollary}