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23 lines
643 B
23 lines
643 B
8 years ago

### Output of FFT:






```



{[DC,NY],C[1],C[2],...,C[n/2]}



```






### On a sample basis



Let ps stand for "per sample"






``` C[1] ``` gives the ```1/N``` ps coefficient






``` C[2] ``` gives the ```2/N``` ps coefficient






``` C[N/2] ``` gives the ```1/2``` ps coefficient
### In seconds
Let ```f``` (=44100) be the samplerate. Then:






``` C[1] ``` gives the ```f/N``` hz coefficient






``` C[2] ``` gives the ```2f/N``` hz coefficient






``` C[N/2] ``` gives the ```f/2``` hz coefficient






### From herz to position



Let ```h``` be some frequency. Then from the above we see that for ``` m := Nh/f ``` we get the ```mf/N = h``` hz coefficient in ``` C[m]```.
